Bear and Poker CodeForces - 573A-白红宇

Bear and Poker CodeForces - 573A

阅读量：259 次

发布时间：2019-03-01

本文共 1005 字，大约阅读时间需要 3 分钟。

????n??????????3??????2???????????????????

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???????????????2^a * 3^b * k??????k??2?3?????k?????????????2?3??????

???k???????k?????????????a?b???????????????????k????????????2?3????????

??????????k????????????2?3???????

?????

????????????????2?3??????

????????????????

????????YES????????NO??

?????

#include 
   
    #include 
    
     #include 
     
      #include 
      #include 
       
        #include 
        
         #include 
         
          #include 
          
           #include 
           
            using namespace std;int root(int x) { while (x % 2 == 0) x /= 2; while (x % 3 == 0) x /= 3; return x;}int main() { int n; cin >> n; vector
            
              a(n); for (int i = 0; i < n; ++i) { a[i] = root(a[i]); } bool same = true; int first = a[0]; for (size_t i = 1; i < n; ++i) { if (a[i] != first) { same = false; break; } } if (same) { cout << "YES"; } else { cout << "NO"; }}

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??????????????YES???NO??

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