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Bear and Poker CodeForces - 573A
阅读量:259 次
发布时间:2019-03-01

本文共 1005 字,大约阅读时间需要 3 分钟。

????n??????????3??????2???????????????????

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  • ???????????????2^a * 3^b * k??????k??2?3?????k?????????????2?3??????

  • ???k???????k?????????????a?b???????????????????k????????????2?3????????

  • ??????????k????????????2?3???????

  • ?????

  • ????????????????2?3??????
  • ????????????????
  • ????????YES????????NO??
  • ?????

    #include 
    #include
    #include
    #include
    #include
    #include
    #include
    #include
    #include
    using namespace std;int root(int x) { while (x % 2 == 0) x /= 2; while (x % 3 == 0) x /= 3; return x;}int main() { int n; cin >> n; vector
    a(n); for (int i = 0; i < n; ++i) { a[i] = root(a[i]); } bool same = true; int first = a[0]; for (size_t i = 1; i < n; ++i) { if (a[i] != first) { same = false; break; } } if (same) { cout << "YES"; } else { cout << "NO"; }}

    ???

    • ????????root??????????????2?3?????????????
    • ???????????n????????
    • ????????????????????2?3?????????????
    • ??????????????????????
    • ??????????????YES???NO??

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